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5v^2-38v+21=0
a = 5; b = -38; c = +21;
Δ = b2-4ac
Δ = -382-4·5·21
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-32}{2*5}=\frac{6}{10} =3/5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+32}{2*5}=\frac{70}{10} =7 $
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